Once you get the hang of it though it's super easy. No better time to start then When I first encountered subnetting I had to read through a few approaches before it finally stuck with me. Subnetting may not be a huge part of the test, but it's definitely something that OP should learn if they plan on advancing in the field. Subnetting may also not be a huge part of the test. Since they give little dry erase sheets during exams, it's easy to quickly jot a chart down and reference it when the questions come up. If you have access to the Sybex book for the 70-410 exam, the explanation and charts are much better. Practice and check your results against this chart: Opens a new window 2^12 = 4096 which are enough addresses to cover the request. Working backwards (using the 0s) is easier since you can memorize the powers of 2. If you're asked to come up with a subnet mask with at least 4000 addresses, you can multiply 254 until you figure it out but that's not easy. You can have 4064 hosts with the /20 subnet mask. You can have 16 networks with that mask.Īddresses range from 0 to 255 for 256 total addresses but 0 and 255 are reserved leaving 254 addressable addresses. The last "1" in the mask represents the value "16". The heart of it is learning to calculate the binary values of the subnet mask. So the network address is going to be 186.29.167.This may not be the easiest or most correct but it's the way I've been able to memorize subnetting: ![]() You have to remember and keep in mind that number under "Addresses" which we said was 4 So, the number closest to 150 that is a number divisible by 4 is 148, now what I did was start with the number 160 since that is a number divisible by 4 and just subtracted 12 and got 148 So, to get the network address ALL you have to do is.įind the number divisible by 4 that is closest to 150, because since the 4th octet is 252 you can't bring down the number from the IP Address. NOW this is the trick, you see the number under "Addresses" the number there is 4, right? Say the question is to find the network address, the broadcast address, and obviously the subnet mask.ġ86.29.167.150/30 <- If you're familiar with Professor Messers chart, you'd know that the /30 gives you the number 252 for the 4th octet. I figured this would help alot of people out as most people don't like his method because of the bottom chart. And so I was just looking and looking trying to figure it out and i'm not even sure how I came to this solution that makes the bottom chart useless, you DON'T need it. So for hours on end I was trying to figure out how I was going to memorize the bottom chart in Professor Messers 7 second subnetting video. ![]() ![]() r/CompTIA holds no responsibility for certification nullification which may be caused by visiting links submitted to this subreddit.Īsking for, or posting links to Braindumps, Unauthorized reproduction of testing material, copyrighted material or other content that is in violation of the CompTIA Candidate Agreement will result in removal of post, up to being banned from this community. Note Please be advised that the use of some of the links above may violate CompTIA's certification policies.
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